What is the inverse of f(x)=(x-2)^2+5 ?

The inverse of f(x)=(x-2)^2+5 is sqrt(x-5)+2,-sqrt(x-5)+2

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inverse of f(x)=(x-2)^2+5

inverse

f (x) = (x - 2)^{2} + 5

x - 5 + 2, - x - 5 + 2

Solution steps

y = (x - 2)^{2} + 5

Replace

x

with

y

x = (y - 2)^{2} + 5

Solve for

y, x = (y - 2)^{2} + 5

x - 5 + 2, - x - 5 + 2

f (x) = \frac{x + 1}{2 x + 39 + x}

x^{3} (x + 5)^{2} + 5

ln (tan (x) + sec (x))

f (x) = \frac{1}{x - 6}

What is the inverse of f(x)=(x-2)^2+5 ?
The inverse of f(x)=(x-2)^2+5 is sqrt(x-5)+2,-sqrt(x-5)+2