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Popular >

midpoint (3,-1),(-1,9)

Solution

midpoint

(3, - 1), (- 1, 9)

Solution

(1, 4)

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (3, - 1), (x_{2}, y_{2}) = (- 1, 9)

= (\frac{- 1 + 3}{2}, \frac{9 - 1}{2})

Refine

= (1, 4)

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domain of f(t)=(arctan(t),(1-e^{-2t})/t)domain

f (t) = (arctan (t), \frac{1 - e ^{- 2 t}}{t})

Frequently Asked Questions (FAQ)

What is the midpoint (3,-1),(-1,9) ?
The midpoint (3,-1),(-1,9) is (1,4)