What is the inverse of f(x)=e^{x^3-7}+1 ?

The inverse of f(x)=e^{x^3-7}+1 is cube root of ln(x-1)+7

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inverse of f(x)=e^{x^3-7}+1

inverse

f (x) = e^{x^{3} - 7} + 1

Solution steps

y = e^{x^{3} - 7} + 1

Replace

x

with

y

x = e^{y^{3} - 7} + 1

Solve for

y, x = e^{y^{3} - 7} + 1

\frac{63}{x ( x + 9 )}

f (x) = 8^{x}

f (x) = 11 x^{2} + 4 y = 44

4 x - 3 y = 21

3 sin (2 x - \frac{π}{4}) + 1

What is the inverse of f(x)=e^{x^3-7}+1 ?
The inverse of f(x)=e^{x^3-7}+1 is cube root of ln(x-1)+7