What is the domain of f(x)=\sqrt[3]{x^3+9} ?

The domain of f(x)=\sqrt[3]{x^3+9} is -infinity <x<infinity

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domain of f(x)=\sqrt[3]{x^3+9}

domain

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

g (x) = 3^{x - 3}

4 - t^{2}

\frac{x}{3 x - 1}

\frac{1}{x - a}

4 x + 6

What is the domain of f(x)=\sqrt[3]{x^3+9} ?
The domain of f(x)=\sqrt[3]{x^3+9} is -infinity <x<infinity