What is the perpendicular y=-6x+3,(-6,7) ?

The perpendicular y=-6x+3,(-6,7) is y= 1/6 x+8

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perpendicular y=-6x+3,(-6,7)

perpendicular

y = - 6 x + 3, (- 6, 7)

y = \frac{1}{6} x + 8

Solution steps

Find the line

y = mx + b

perpendicular to

y = - 6 x + 3

that passes through

(- 6, 7)

Find the slope of

y = - 6 x + 3 : m = - 6

Compute the slope of the perpendicular line:

m_{p} = \frac{1}{6}

Find the line with slope m=

\frac{1}{6}

and passing through

(- 6, 7) : y = \frac{1}{6} x + 8

y = \frac{1}{6} x + 8

\frac{1}{1 + x}

f (x) = x^{2} - 4 x + 7

f (x) = \frac{1}{x ^{2} - 3 x + 2}

f (x) = ln (3 x + 1)

f (x) = \frac{5 + x}{5 - x}

What is the perpendicular y=-6x+3,(-6,7) ?
The perpendicular y=-6x+3,(-6,7) is y= 1/6 x+8