What is the inverse of f(x)=x^{1/5}+7 ?

The inverse of f(x)=x^{1/5}+7 is x^5-35x^4+490x^3-3430x^2+12005x-16807

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inverse of f(x)=x^{1/5}+7

inverse

f (x) = x^{\frac{1}{5}} + 7

x^{5} - 35 x^{4} + 490 x^{3} - 3430 x^{2} + 12005 x - 16807

Solution steps

y = x^{\frac{1}{5}} + 7

Replace

x

with

y

x = y^{\frac{1}{5}} + 7

Solve for

y, x = y^{\frac{1}{5}} + 7

x^{5} - 35 x^{4} + 490 x^{3} - 3430 x^{2} + 12005 x - 16807

\frac{x + 1}{x - 1}

y (X) = X^{4} - X^{2} + 3

f (x) = 3 x + 4 y = 6

\frac{2}{x ^{3}}

What is the inverse of f(x)=x^{1/5}+7 ?
The inverse of f(x)=x^{1/5}+7 is x^5-35x^4+490x^3-3430x^2+12005x-16807