What is the domain of f(x)= 1/(x^2+6x-16) ?

The domain of f(x)= 1/(x^2+6x-16) is x 2

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domain of f(x)= 1/(x^2+6x-16)

domain

f (x) = \frac{1}{x ^{2} + 6 x - 16}

x < - 8 or - 8 < x < 2 or x > 2

Interval Notation

(- \infty, - 8) \cup (- 8, 2) \cup (2, \infty)

Solution steps

Find undefined (singularity) points:

x = 2, x = - 8

The function domain

x < - 8 or - 8 < x < 2 or x > 2

x^{3} - 3

- x^{3} + 6 x^{2} - 15

x^{2} + 2

f (x) = lo g_{2} (x - 3)

y^{2} = x + 16

What is the domain of f(x)= 1/(x^2+6x-16) ?
The domain of f(x)= 1/(x^2+6x-16) is x<-8\lor-8<x<2\lor x>2