What is the domain of f(x)= 1/(sqrt(4x-3)) ?

The domain of f(x)= 1/(sqrt(4x-3)) is x> 3/4

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domain of f(x)= 1/(sqrt(4x-3))

domain

f (x) = \frac{1}{4 x - 3}

x > \frac{3}{4}

Interval Notation

(\frac{3}{4}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq \frac{3}{4}

Find undefined (singularity) points:

x = \frac{3}{4}

Combine real regions and undefined points for final function domain

x > \frac{3}{4}

csc (x)

f (x) = 16 - x^{2}

13, - 11

f (x) = 3 x^{2} - 2

(3.2) (7.6)

What is the domain of f(x)= 1/(sqrt(4x-3)) ?
The domain of f(x)= 1/(sqrt(4x-3)) is x> 3/4