What is the inverse of f(x)=(x^2-4)/(3x^2) ?

The inverse of f(x)=(x^2-4)/(3x^2) is sqrt(-4/(3x-1)),-sqrt(-4/(3x-1))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=(x^2-4)/(3x^2)

inverse

f (x) = \frac{x ^{2} - 4}{3 x ^{2}}

- \frac{4}{3 x - 1}, - - \frac{4}{3 x - 1}

Solution steps

y = \frac{x ^{2} - 4}{3 x ^{2}}

Replace

x

with

y

x = \frac{y ^{2} - 4}{3 y ^{2}}

Solve for

y, x = \frac{y ^{2} - 4}{3 y ^{2}}

- \frac{4}{3 x - 1}, - - \frac{4}{3 x - 1}

cos (sin (tan (5 x)))

f (x) = \frac{8 - 3 x}{x ^{2} - 2 x}

f (x) = - 5 x - 5

x^{3} - \frac{3}{2} x^{2}

f (x) = 100 - x^{2}

What is the inverse of f(x)=(x^2-4)/(3x^2) ?
The inverse of f(x)=(x^2-4)/(3x^2) is sqrt(-4/(3x-1)),-sqrt(-4/(3x-1))