What is the inverse of f(x)=18500(0.04-x^2) ?

The inverse of f(x)=18500(0.04-x^2) is sqrt(-0.00005…x+0.04),-sqrt(-0.00005…x+0.04)

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inverse of f(x)=18500(0.04-x^2)

inverse

f (x) = 18500 (0.04 - x^{2})

- 0.00005 \dots x + 0.04, - - 0.00005 \dots x + 0.04

Solution steps

y = 18500 (0.04 - x^{2})

Replace

x

with

y

x = 18500 (0.04 - y^{2})

Solve for

y, x = 18500 (0.04 - y^{2})

- 0.00005 \dots x + 0.04, - - 0.00005 \dots x + 0.04

x e^{x}

f (x) = \frac{5}{x + 3}

f (x) = 2 t^{\frac{2}{3}} + t^{\frac{5}{3}}

f (x) = \frac{3}{1 - x ^{2}}

What is the inverse of f(x)=18500(0.04-x^2) ?
The inverse of f(x)=18500(0.04-x^2) is sqrt(-0.00005…x+0.04),-sqrt(-0.00005…x+0.04)