What is the domain of f(x)=sqrt(2+3x) ?

The domain of f(x)=sqrt(2+3x) is x>=-2/3

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domain of f(x)=sqrt(2+3x)

domain

f (x) = 2 + 3 x

x \geq - \frac{2}{3}

Interval Notation

[- \frac{2}{3}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - \frac{2}{3}

The function domain

x \geq - \frac{2}{3}

5 x^{4} - 2 sec^{2} (x)

y = 2^{x}

\frac{1}{x + 1} + 2

f (x) = 15 - x^{2}

f (x) = 36 - x^{2} + x + 3

What is the domain of f(x)=sqrt(2+3x) ?
The domain of f(x)=sqrt(2+3x) is x>=-2/3