What is the inverse of f(x)=(4x+8)/(3x+4) ?

The inverse of f(x)=(4x+8)/(3x+4) is (8-4x)/(3x-4)

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inverse of f(x)=(4x+8)/(3x+4)

inverse

f (x) = \frac{4 x + 8}{3 x + 4}

\frac{8 - 4 x}{3 x - 4}

Solution steps

y = \frac{4 x + 8}{3 x + 4}

Replace

x

with

y

x = \frac{4 y + 8}{3 y + 4}

Solve for

y, x = \frac{4 y + 8}{3 y + 4}

\frac{8 - 4 x}{3 x - 4}

f (x) = 5 - x + 10

f (x) = arcsin (x) - arccos (x)

f (x) = \frac{1 - x}{x - 1}

y = - 2 x + 4

f (x) = 7 x^{2}

What is the inverse of f(x)=(4x+8)/(3x+4) ?
The inverse of f(x)=(4x+8)/(3x+4) is (8-4x)/(3x-4)