What is the domain of y=sqrt(x^2-5x+6) ?

The domain of y=sqrt(x^2-5x+6) is x = 3

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domain of y=sqrt(x^2-5x+6)

domain

y = x^{2} - 5 x + 6

x \leq 2 or x \geq 3

Interval Notation

(- \infty, 2] \cup [3, \infty)

Solution steps

Find non-negative values for radicals:

x \leq 2 or x \geq 3

The function domain

x \leq 2 or x \geq 3

f (x) = ln (10 x)

ln (x - 2)

f (x) = 2 x^{2} - 6

x^{4} + 4 x

f (x) = (\frac{4}{3})^{- x}

What is the domain of y=sqrt(x^2-5x+6) ?
The domain of y=sqrt(x^2-5x+6) is x<= 2\lor x>= 3