What is the perpendicular y=-3x+1,(3,5) ?

The perpendicular y=-3x+1,(3,5) is y= 1/3 x+4

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perpendicular y=-3x+1,(3,5)

perpendicular

y = - 3 x + 1, (3, 5)

y = \frac{1}{3} x + 4

Solution steps

Find the line

y = mx + b

perpendicular to

y = - 3 x + 1

that passes through

(3, 5)

Find the slope of

y = - 3 x + 1 : m = - 3

Compute the slope of the perpendicular line:

m_{p} = \frac{1}{3}

Find the line with slope m=

\frac{1}{3}

and passing through

(3, 5) : y = \frac{1}{3} x + 4

y = \frac{1}{3} x + 4

(30.8) (40.7)

4 cos (2 (x + \frac{π}{4})) - 3

2 x + 2

f (x) = e^{3 x - 2}

sin (x + \frac{3 π}{2})

What is the perpendicular y=-3x+1,(3,5) ?
The perpendicular y=-3x+1,(3,5) is y= 1/3 x+4