What is the domain of f(x)=sqrt(2x^2-13x-24) ?

The domain of f(x)=sqrt(2x^2-13x-24) is x = 8

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domain of f(x)=sqrt(2x^2-13x-24)

domain

f (x) = 2 x^{2} - 13 x - 24

x \leq - \frac{3}{2} or x \geq 8

Interval Notation

(- \infty, - \frac{3}{2}] \cup [8, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - \frac{3}{2} or x \geq 8

The function domain

x \leq - \frac{3}{2} or x \geq 8

f (x) = 6^{x}

f (x) = - x^{3} - 4

f (x) = x^{4} - 4 x^{3}

f (x) = \frac{t ^{2} - 2 t}{t ^{4} - 16}

y = \frac{7}{6} x

What is the domain of f(x)=sqrt(2x^2-13x-24) ?
The domain of f(x)=sqrt(2x^2-13x-24) is x<=-3/2 \lor x>= 8