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Popular >

extreme f(x)=x^2-2x+2

Solution

extreme points

f (x) = x^{2} - 2 x + 2

Solution

Minimum (1, 1)

Solution steps

f^{'} (x) = 2 x - 2

Find intervals:

Decreasing

: - \infty < x < 1,

Increasing

: 1 < x < \infty

Plug

x = 1

into

x^{2} - 2 x + 2 : 1

Minimum (1, 1)

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Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^2-2x+2 ?
The extreme f(x)=x^2-2x+2 is Minimum(1,1)