What is the inverse of f(x)=\sqrt[3]{(-x+2)/2} ?

The inverse of f(x)=\sqrt[3]{(-x+2)/2} is -2x^3+2

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inverse of f(x)=\sqrt[3]{(-x+2)/2}

inverse

f (x) = 3 \frac{- x + 2}{2}

- 2 x^{3} + 2

Solution steps

y = 3 \frac{- x + 2}{2}

Replace

x

with

y

x = 3 \frac{- y + 2}{2}

Solve for

y, x = 3 \frac{- y + 2}{2}

- 2 x^{3} + 2

f (x) = \frac{3 x + ∣ x ∣}{x}

y = \frac{x}{2} - 9, (8, - 7)

\frac{x - 6}{x + 2}

f (x) = \frac{5 x ^{2} + 6}{7 x + 5}

\frac{1}{x ^{2} - 5 x + 6}

What is the inverse of f(x)=\sqrt[3]{(-x+2)/2} ?
The inverse of f(x)=\sqrt[3]{(-x+2)/2} is -2x^3+2