What is the extreme f(x)=4x+1,0<= x<1 ?

The extreme f(x)=4x+1,0<= x<1 is Minimum(0,1)

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extreme f(x)=4x+1,0<= x<1

extreme points

f (x) = 4 x + 1, 0 \leq x < 1

Minimum (0, 1)

Solution steps

Find the critical points:

x = 0

Domain of

4 x + 1, 0 \leq x < 1 : 0 \leq x < 1

Find intervals:

Increasing

: 0 < x < 1

Plug the extreme point

x = 0

into

4 x + 1 \Rightarrow y = 1

Minimum (0, 1)

(38) (3 - 6)

\frac{10 x - 1}{3 - 5 x}

1 1^{23}

h (x) = ln (x) + ln (5 - x)

f (x) = \frac{( 13 - 2 x )}{x - 3}

What is the extreme f(x)=4x+1,0<= x<1 ?
The extreme f(x)=4x+1,0<= x<1 is Minimum(0,1)