What is the inverse of sqrt(9-x^2) ?

The inverse of sqrt(9-x^2) is sqrt(-x^2+9),-sqrt(-x^2+9)

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inverse of sqrt(9-x^2)

inverse

9 - x^{2}

- x^{2} + 9, - - x^{2} + 9

Solution steps

y = 9 - x^{2}

Replace

x

with

y

x = 9 - y^{2}

Solve for

y, x = 9 - y^{2}

- x^{2} + 9, - - x^{2} + 9

f (x) = x^{2} - 2

y = \frac{- 3}{2} x - 5, (\frac{4}{7}, 2)

- \frac{7}{9} cos (\frac{9}{8} x)

\frac{x - 6}{4 x - 8}

y = 5 x + 2

What is the inverse of sqrt(9-x^2) ?
The inverse of sqrt(9-x^2) is sqrt(-x^2+9),-sqrt(-x^2+9)