What is the critical f(x)=(x+5)e^{-2x} ?

The critical f(x)=(x+5)e^{-2x} is x=-9/2

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critical f(x)=(x+5)e^{-2x}

critical points

f (x) = (x + 5) e^{- 2 x}

x = - \frac{9}{2}

Solution steps

(x + 5) e^{- 2 x}

Find where

f^{'} (x)

is equal to zero or undefined

x = - \frac{9}{2}

Identify critical points not in

f (x)

domain

Domain of

(x + 5) e^{- 2 x} : - \infty < x < \infty

All critical points are in domain

x = - \frac{9}{2}

x^{2} + 4 x

2 e^{- x} - 3

f (x) = \frac{x + 3}{x ^{2} + 2 x - 3}

f (x) = \frac{x + 5}{x - 1}

x^{3} + 4

What is the critical f(x)=(x+5)e^{-2x} ?
The critical f(x)=(x+5)e^{-2x} is x=-9/2