What is the domain of f(x)=sqrt(x-3)+4 ?

The domain of f(x)=sqrt(x-3)+4 is x>= 3

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domain of f(x)=sqrt(x-3)+4

domain

f (x) = x - 3 + 4

x \geq 3

Interval Notation

[3, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 3

The function domain

x \geq 3

f (x) = \frac{1}{x + 2} + 9

f (x) = \frac{x - 1}{2 + x}

\frac{2}{( 2 x - 5 )}

f (x) = 2 x^{2} + x - 3

x^{2} - 3 x - 54

What is the domain of f(x)=sqrt(x-3)+4 ?
The domain of f(x)=sqrt(x-3)+4 is x>= 3