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Popular >

extreme f(x)=ln(x^2+1)

Solution

extreme points

f (x) = ln (x^{2} + 1)

Solution

Minimum (0, 0)

Solution steps

f^{'} (x) = \frac{2 x}{x ^{2} + 1}

Find intervals:

Decreasing

: - \infty < x < 0,

Increasing

: 0 < x < \infty

Plug

x = 0

into

ln (x^{2} + 1) : 0

Minimum (0, 0)

Popular Examples

asymptotes of 2^x-3 asymptotes

2^{x} - 3

range of \sqrt[3]{2x-4}range

asymptotes of f(x)=(12x)/(x^2-144)asymptotes

f (x) = \frac{12 x}{x ^{2} - 144}

asymptotes of 1/(x-3)asymptotes

\frac{1}{x - 3}

distance (-4,-6),(-9,6)distance

(- 4, - 6), (- 9, 6)

Frequently Asked Questions (FAQ)

What is the extreme f(x)=ln(x^2+1) ?
The extreme f(x)=ln(x^2+1) is Minimum(0,0)