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Popular >

range of f(x)=x^2+2x-8

Solution

range

f (x) = x^{2} + 2 x - 8

Solution

f (x) \geq - 9

+1

Interval Notation

[- 9, \infty)

Solution steps

Vertex of

x^{2} + 2 x - 8 :

Minimum

(- 1, - 9)

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = 1,

Vertex

(x_{v}, y_{v}) = (- 1, - 9)

f (x) \geq - 9

Popular Examples

intercepts of f(x)=x^2-6x-7 intercepts

f (x) = x^{2} - 6 x - 7

parallel 3x+5y=45,(-5,6)parallel

3 x + 5 y = 45, (- 5, 6)

line 2(x-3)-4(y+2)=8 line

2 (x - 3) - 4 (y + 2) = 8

symmetry 4-(x-3)^2 symmetry

4 - (x - 3)^{2}

domain of f(x)=(x-7)/(x+5)domain

f (x) = \frac{x - 7}{x + 5}

Frequently Asked Questions (FAQ)

What is the range of f(x)=x^2+2x-8 ?
The range of f(x)=x^2+2x-8 is f(x)>=-9