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Popular >

distance (6,4),(-1,-3)

Solution

distance

(6, 4), (- 1, - 3)

Solution

72

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(6, 4)

and

(- 1, - 3)

is

= (- 1 - 6)^{2} + (- 3 - 4)^{2}

Simplify

= 72

Popular Examples

extreme f(x)=xsqrt(400-x^2)extreme points

f (x) = x 400 - x^{2}

parity y=(tan(-arctan(x^2)+c))/2 parity

y = \frac{tan ( - arctan ( x ^{2} ) + c )}{2}

extreme f(x)=-x^3+6x^2-5 extreme points

f (x) = - x^{3} + 6 x^{2} - 5

f (x) = \frac{3}{x}

critical e^{7x}+7e^{7x}x critical points

e^{7 x} + 7 e^{7 x} x

Frequently Asked Questions (FAQ)

What is the distance (6,4),(-1,-3) ?
The distance (6,4),(-1,-3) is 7sqrt(2)