What is the domain of f(x)=(sqrt(x+7))/(x-3) ?

The domain of f(x)=(sqrt(x+7))/(x-3) is -7 3

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domain of f(x)=(sqrt(x+7))/(x-3)

domain

f (x) = \frac{x + 7}{x - 3}

- 7 \leq x < 3 or x > 3

Interval Notation

[- 7, 3) \cup (3, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 7

Find undefined (singularity) points:

x = 3

Combine real regions and undefined points for final function domain

- 7 \leq x < 3 or x > 3

f (x) = \frac{x ^{2} + 6 x + 5}{x ^{2} + 5 x + 6}

f (x) = x^{4} - 3

f (x) = \frac{2 x - 4}{x ^{2} + x - 2}

f (x) = 1 - x^{2}

What is the domain of f(x)=(sqrt(x+7))/(x-3) ?
The domain of f(x)=(sqrt(x+7))/(x-3) is -7<= x<3\lor x>3