What is the asymptotes of f(x)=(4x^2+8x-9)/(2x+1) ?

The asymptotes of f(x)=(4x^2+8x-9)/(2x+1) is Vertical: x=-1/2 ,Slant: y=2x+3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

asymptotes of f(x)=(4x^2+8x-9)/(2x+1)

asymptotes

f (x) = \frac{4 x ^{2} + 8 x - 9}{2 x + 1}

Vertical : x = - \frac{1}{2}, Slant : y = 2 x + 3

Solution steps

Vertical asymptotes of

\frac{4 x ^{2} + 8 x - 9}{2 x + 1} : x = - \frac{1}{2}

Horizontal Asymptotes of

\frac{4 x ^{2} + 8 x - 9}{2 x + 1} :

None

Slant Asymptotes of

\frac{4 x ^{2} + 8 x - 9}{2 x + 1} : y = 2 x + 3

Vertical : x = - \frac{1}{2}, Slant : y = 2 x + 3

f (x) = 3 x + 5

h

1 - x + 2

y = 10 x

f (x) = ln (x) + ln (2 - x)

What is the asymptotes of f(x)=(4x^2+8x-9)/(2x+1) ?
The asymptotes of f(x)=(4x^2+8x-9)/(2x+1) is Vertical: x=-1/2 ,Slant: y=2x+3