What is the critical f(x,y)=4x^3 ?

The critical f(x,y)=4x^3 is x=0

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critical f(x,y)=4x^3

critical points

f (x, y) = 4 x^{3}

x = 0

Solution steps

4 x^{3}

Find where

f^{'} (x)

is equal to zero or undefined

x = 0

Identify critical points not in

f (x)

domain

Domain of

4 x^{3} : - \infty < x < \infty

All critical points are in domain

x = 0

f (x) = - 2 sin (- 3 x + \frac{π}{2})

f (x) = - x^{3} + 3 x^{2} - 4

x - 2 y = - 8

f (x) = x + 1 + 3

f (x) = \frac{2 - x ^{2}}{x + 2}