What is the range of f(x)=(x^2+6x-7)/(x^2+2x-3) ?

The range of f(x)=(x^2+6x-7)/(x^2+2x-3) is f(x) 2

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range of f(x)=(x^2+6x-7)/(x^2+2x-3)

range

f (x) = \frac{x ^{2} + 6 x - 7}{x ^{2} + 2 x - 3}

f (x) < 1 or 1 < f (x) < 2 or f (x) > 2

Interval Notation

(- \infty, 1) \cup (1, 2) \cup (2, \infty)

Solution steps

Find the minimum and maximum value in each defined interval and unite the results

Domain of

\frac{x ^{2} + 6 x - 7}{x ^{2} + 2 x - 3} : x < - 3 or - 3 < x < 1 or x > 1

Simplify

\frac{x ^{2} + 6 x - 7}{x ^{2} + 2 x - 3} : \frac{x + 7}{x + 3}

Extreme Points of

\frac{x + 7}{x + 3} :

None

Find the range for the interval

- \infty < x < - 3 : - \infty < f (x) < 1

Find the range for the interval

- 3 < x < 1 : 2 < f (x) < \infty

Find the range for the interval

1 < x < \infty : 1 < f (x) < 2

Combine the ranges of all domain intervals to obtain the function range

f (x) < 1 or f (x) > 2 or 1 < f (x) < 2

f (x) < 1 or 1 < f (x) < 2 or f (x) > 2

y = - \frac{1}{3} x^{3} + 2 x^{2} - 1

y = (x - 2)^{3}

f (x) = x^{2} - 36

f (x) = e^{- x} + 2

2 (x + 3)^{2} - 2

What is the range of f(x)=(x^2+6x-7)/(x^2+2x-3) ?
The range of f(x)=(x^2+6x-7)/(x^2+2x-3) is f(x)<1\lor 1<f(x)<2\lor f(x)>2