What is the inverse of f(x)=x-x^2 ?

The inverse of f(x)=x-x^2 is -(-1+sqrt(1-4x))/2 ,-(-1-sqrt(1-4x))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=x-x^2

inverse

f (x) = x - x^{2}

- \frac{- 1 + 1 - 4 x}{2}, - \frac{- 1 - 1 - 4 x}{2}

Solution steps

y = x - x^{2}

Replace

x

with

y

x = y - y^{2}

Solve for

y, x = y - y^{2}

- \frac{- 1 + 1 - 4 x}{2}, - \frac{- 1 - 1 - 4 x}{2}

\frac{7 x}{9 x - 1}

(0) (2.8)

\frac{x - 9}{x - 3}

y = 5 - x

What is the inverse of f(x)=x-x^2 ?
The inverse of f(x)=x-x^2 is -(-1+sqrt(1-4x))/2 ,-(-1-sqrt(1-4x))/2