What is the perpendicular y=5x+2,\at x=1 ?

The perpendicular y=5x+2,\at x=1 is y=-1/5 x+36/5

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perpendicular y=5x+2,\at x=1

perpendicular

y = 5 x + 2, at x = 1

y = - \frac{1}{5} x + \frac{36}{5}

Solution steps

Find the line

y = mx + b

perpendicular to

y = 5 x + 2

that passes through

x = 1

Find the perpendicular point:

(1, 7)

Find the slope of

y = 5 x + 2 : m = 5

Compute the slope of the perpendicular line:

m_{p} = - \frac{1}{5}

Find the line with slope m=

- \frac{1}{5}

and passing through

(1, 7) : y = - \frac{1}{5} x + \frac{36}{5}

y = - \frac{1}{5} x + \frac{36}{5}

f (x) = \frac{2}{x - 6}

f (x) = \frac{x - 5}{x ^{2} - 25}

f (x) = \frac{1 - 2 t}{( t + 6 )}

- x^{4} + 12 x^{3} - 12 x + 13

f (x) = 2 x - 5

What is the perpendicular y=5x+2,\at x=1 ?
The perpendicular y=5x+2,\at x=1 is y=-1/5 x+36/5