What is the domain of (4x^2-5)/(2x^2+8) ?

The domain of (4x^2-5)/(2x^2+8) is -infinity <x<infinity

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domain of (4x^2-5)/(2x^2+8)

domain

\frac{4 x ^{2} - 5}{2 x ^{2} + 8}

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

\frac{x ^{2} + 1}{x}

x^{2} + 6

f (x) = sin (sin (x))

2 x + 5 y = 5

x^{2} - 6 x + 8

What is the domain of (4x^2-5)/(2x^2+8) ?
The domain of (4x^2-5)/(2x^2+8) is -infinity <x<infinity