What is the inverse of f(x)=(x-1)^2+1 ?

The inverse of f(x)=(x-1)^2+1 is sqrt(x-1)+1,-sqrt(x-1)+1

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inverse of f(x)=(x-1)^2+1

inverse

f (x) = (x - 1)^{2} + 1

x - 1 + 1, - x - 1 + 1

Solution steps

y = (x - 1)^{2} + 1

Replace

x

with

y

x = (y - 1)^{2} + 1

Solve for

y, x = (y - 1)^{2} + 1

x - 1 + 1, - x - 1 + 1

f (- x) = \frac{1}{2 x}

\frac{2 x - 6}{x + 6}

f (x) = x^{\frac{11}{5}} - x^{\frac{6}{5}}

f (x) = 2 cos (x)

y = \frac{3}{x + 2}

What is the inverse of f(x)=(x-1)^2+1 ?
The inverse of f(x)=(x-1)^2+1 is sqrt(x-1)+1,-sqrt(x-1)+1