What is the inverse of f(x)=(x^2-16)/(3x^2) ?

The inverse of f(x)=(x^2-16)/(3x^2) is sqrt(-(16)/(3x-1)),-sqrt(-(16)/(3x-1))

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inverse of f(x)=(x^2-16)/(3x^2)

inverse

f (x) = \frac{x ^{2} - 16}{3 x ^{2}}

- \frac{16}{3 x - 1}, - - \frac{16}{3 x - 1}

Solution steps

y = \frac{x ^{2} - 16}{3 x ^{2}}

Replace

x

with

y

x = \frac{y ^{2} - 16}{3 y ^{2}}

Solve for

y, x = \frac{y ^{2} - 16}{3 y ^{2}}

- \frac{16}{3 x - 1}, - - \frac{16}{3 x - 1}

f (x) = \frac{9 + x}{6 - x}

x^{3} - 5 x^{2} + 13

f (x) = x (x - 1)

x^{4} - 24 x^{2} + 75

(8, 1230), (16, 2430)

What is the inverse of f(x)=(x^2-16)/(3x^2) ?
The inverse of f(x)=(x^2-16)/(3x^2) is sqrt(-(16)/(3x-1)),-sqrt(-(16)/(3x-1))