What is the inverse of h(x)=(x+1)(x-2) ?

The inverse of h(x)=(x+1)(x-2) is (1+sqrt(4x+9))/2 ,(1-sqrt(4x+9))/2

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inverse of h(x)=(x+1)(x-2)

inverse

h (x) = (x + 1) (x - 2)

\frac{1 + 4 x + 9}{2}, \frac{1 - 4 x + 9}{2}

Solution steps

y = (x + 1) (x - 2)

Replace

x

with

y

x = (y + 1) (y - 2)

Solve for

y, x = (y + 1) (y - 2)

\frac{1 + 4 x + 9}{2}, \frac{1 - 4 x + 9}{2}

6 x - y = 5, (6, 5)

2 x - y = 3

f (x) = - 3^{x + 1}

f (x) = x^{2} - x - 6

f (x) = \frac{1}{4} x - 6

What is the inverse of h(x)=(x+1)(x-2) ?
The inverse of h(x)=(x+1)(x-2) is (1+sqrt(4x+9))/2 ,(1-sqrt(4x+9))/2