What is the extreme f(x)=-16t^2+30t+5 ?

The extreme f(x)=-16t^2+30t+5 is Maximum(15/16 , 305/16)

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extreme f(x)=-16t^2+30t+5

extreme points

f (x) = - 16 t^{2} + 30 t + 5

Maximum (\frac{15}{16}, \frac{305}{16})

Solution steps

f^{'} (t) = - 32 t + 30

Find intervals:

Increasing

: - \infty < t < \frac{15}{16},

Decreasing

: \frac{15}{16} < t < \infty

Plug

t = \frac{15}{16}

into

- 16 t^{2} + 30 t + 5 : \frac{305}{16}

Maximum (\frac{15}{16}, \frac{305}{16})

x^{2} - 2 x + 9

\frac{3}{2} x + 2

y = 4 x^{2} - 16

f (x) = \frac{2 x}{1 + x ^{2}}

f (x) = \frac{3 x - 2}{5}

What is the extreme f(x)=-16t^2+30t+5 ?
The extreme f(x)=-16t^2+30t+5 is Maximum(15/16 , 305/16)