What is the perpendicular x=-19,(6,1) ?

The perpendicular x=-19,(6,1) is y=1

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perpendicular x=-19,(6,1)

perpendicular

x = - 19, (6, 1)

y = 1

Solution steps

Find the line

y = mx + b

perpendicular to

x = - 19

that passes through

(6, 1)

Find the slope of

x = - 19 : m = \infty

Compute the slope of the perpendicular line:

m_{p} = 0

Find the line with slope m=

0

and passing through

(6, 1) : y = 1

y = 1

f (x) = 8 + \frac{4}{x}

y = m x + b

(0, - 7), (- 6, - 2)

f (x) = \frac{1}{5} x - \frac{1}{4}