What is the inverse of f(x)=((x-2)(x-1))/2+1 ?

The inverse of f(x)=((x-2)(x-1))/2+1 is (3+sqrt(8x-7))/2 ,(3-sqrt(8x-7))/2

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inverse of f(x)=((x-2)(x-1))/2+1

inverse

f (x) = \frac{( x - 2 ) ( x - 1 )}{2} + 1

\frac{3 + 8 x - 7}{2}, \frac{3 - 8 x - 7}{2}

Solution steps

y = \frac{( x - 2 ) ( x - 1 )}{2} + 1

Replace

x

with

y

x = \frac{( y - 2 ) ( y - 1 )}{2} + 1

Solve for

y, x = \frac{( y - 2 ) ( y - 1 )}{2} + 1

\frac{3 + 8 x - 7}{2}, \frac{3 - 8 x - 7}{2}

m = - 1, (- 2, 3)

f (x) = cos (\frac{n}{4})

20 x + 28 - 4 y = 0

f (x) = 10 x^{3}

\frac{x ^{5}}{d x}

What is the inverse of f(x)=((x-2)(x-1))/2+1 ?
The inverse of f(x)=((x-2)(x-1))/2+1 is (3+sqrt(8x-7))/2 ,(3-sqrt(8x-7))/2