What is the inverse of f(x)=\sqrt[5]{x-8}+1 ?

The inverse of f(x)=\sqrt[5]{x-8}+1 is x^5-5x^4+10x^3-10x^2+5x+7

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inverse of f(x)=\sqrt[5]{x-8}+1

inverse

x^{5} - 5 x^{4} + 10 x^{3} - 10 x^{2} + 5 x + 7

Solution steps

Replace

x

with

y

Solve for

x^{5} - 5 x^{4} + 10 x^{3} - 10 x^{2} + 5 x + 7

f (x) = \frac{x + 1}{x - 4}

f (x) = 2^{x} - 3

y = x + 3

y = - \frac{2}{3} + 8

f (x) = \frac{5}{x + 1}

What is the inverse of f(x)=\sqrt[5]{x-8}+1 ?
The inverse of f(x)=\sqrt[5]{x-8}+1 is x^5-5x^4+10x^3-10x^2+5x+7