What is the inverse of f(x)=((n+n^2))/2 ?

The inverse of f(x)=((n+n^2))/2 is (-1+sqrt(1+8n))/2 ,(-1-sqrt(1+8n))/2

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inverse of f(x)=((n+n^2))/2

inverse

f (x) = \frac{( n + n ^{2} )}{2}

\frac{- 1 + 1 + 8 n}{2}, \frac{- 1 - 1 + 8 n}{2}

Solution steps

y = \frac{n + n ^{2}}{2}

Replace

n

with

y

n = \frac{y + y ^{2}}{2}

Solve for

y, n = \frac{y + y ^{2}}{2}

\frac{- 1 + 1 + 8 n}{2}, \frac{- 1 - 1 + 8 n}{2}

f (x) = 10 x - x^{2}

f (x) = \frac{5 x - 1}{2}

y = 3 - 4 x

f (x) = - \frac{3}{t}

What is the inverse of f(x)=((n+n^2))/2 ?
The inverse of f(x)=((n+n^2))/2 is (-1+sqrt(1+8n))/2 ,(-1-sqrt(1+8n))/2