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Popular >

range of-x^2+8x-12

Solution

range

- x^{2} + 8 x - 12

Solution

f (x) \leq 4

+1

Interval Notation

(- \infty, 4]

Solution steps

Vertex of

- x^{2} + 8 x - 12 :

Maximum

(4, 4)

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = - 1,

Vertex

(x_{v}, y_{v}) = (4, 4)

f (x) \leq 4

Popular Examples

domain of x^2-x-20 domain

x^{2} - x - 20

slope of x+2y=8 slope

x + 2 y = 8

inverse of f(x)=10(\sqrt[4]{x}-10)inverse

inverse of f(x)=2-5x^2 inverse

f (x) = 2 - 5 x^{2}

parity f(x)=sqrt(3)x parity

f (x) = 3 x

Frequently Asked Questions (FAQ)

What is the range of-x^2+8x-12 ?
The range of-x^2+8x-12 is f(x)<= 4