What is the range of (8+7x)/(6x-7) ?

The range of (8+7x)/(6x-7) is f(x) 7/6

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range of (8+7x)/(6x-7)

range

\frac{8 + 7 x}{6 x - 7}

f (x) < \frac{7}{6} or f (x) > \frac{7}{6}

Interval Notation

(- \infty, \frac{7}{6}) \cup (\frac{7}{6}, \infty)

Solution steps

The function range is the combined domain of the inverse functions

Find the inverse function(s) of:

\frac{8 + 7 x}{6 x - 7}

Inverse of

\frac{8 + 7 x}{6 x - 7} : \frac{8 + 7 x}{6 x - 7}

\frac{8 + 7 x}{6 x - 7}

Find the domain of each inverse function

Domain of

\frac{8 + 7 x}{6 x - 7} : x < \frac{7}{6} or x > \frac{7}{6}

Combine the intervals

f (x) < \frac{7}{6} or f (x) > \frac{7}{6}

(3, 6), (1, - 2)

2 x - 1

f (x) = 1 - 4 x

\frac{( 2 x ^{2} + x )}{x ^{3} + 8 x ^{2} + 15 x}

f (x) = \frac{( x ^{2} + 2 x + 3 )}{x + 1}

What is the range of (8+7x)/(6x-7) ?
The range of (8+7x)/(6x-7) is f(x)< 7/6 \lor f(x)> 7/6