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Popular >

distance (21,-30),(3,8)

Solution

distance

(21, - 30), (3, 8)

Solution

2442

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(21, - 30)

and

(3, 8)

is

= (3 - 21)^{2} + (8 - (- 30))^{2}

Simplify

= 2442

Popular Examples

domain of y=sqrt(1-x^2)domain

y = 1 - x^{2}

midpoint (6,-5),(12,15)midpoint

(6, - 5), (12, 15)

range of f(x)=(-x^2)/(x^2-2x+8)range

f (x) = \frac{- x ^{2}}{x ^{2} - 2 x + 8}

intercepts of f(x)=-0.16x^2+0.96x+6.44 intercepts

f (x) = - 0.16 x^{2} + 0.96 x + 6.44

inverse of (1/2)^x-1 inverse

(\frac{1}{2})^{x} - 1

Frequently Asked Questions (FAQ)

What is the distance (21,-30),(3,8) ?
The distance (21,-30),(3,8) is 2sqrt(442)