What is the inverse of f(x)=3x-x^2 ?

The inverse of f(x)=3x-x^2 is -(-3+sqrt(9-4x))/2 ,-(-3-sqrt(9-4x))/2

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inverse of f(x)=3x-x^2

inverse

f (x) = 3 x - x^{2}

- \frac{- 3 + 9 - 4 x}{2}, - \frac{- 3 - 9 - 4 x}{2}

Solution steps

y = 3 x - x^{2}

Replace

x

with

y

x = 3 y - y^{2}

Solve for

y, x = 3 y - y^{2}

- \frac{- 3 + 9 - 4 x}{2}, - \frac{- 3 - 9 - 4 x}{2}

f (x) = x + 2 + \frac{7}{x - 2}

4 sin (2 x - \frac{π}{3})

\frac{3}{x - 2}

(5, 15), (2, 14)

\frac{( ( x - 1 ) ^{(2)} )}{( x + 1 )}

What is the inverse of f(x)=3x-x^2 ?
The inverse of f(x)=3x-x^2 is -(-3+sqrt(9-4x))/2 ,-(-3-sqrt(9-4x))/2