What is the extreme f(x)=0.1x+24+((330)/x) ?

The extreme f(x)=0.1x+24+((330)/x) is Maximum(-10sqrt(33),12.51087…),Minimum(10sqrt(33),35.48912…)

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extreme f(x)=0.1x+24+((330)/x)

extreme points

f (x) = 0.1 x + 24 + (\frac{330}{x})

Maximum (- 1033, 12.51087 \dots), Minimum (1033, 35.48912 \dots)

Solution steps

Find the critical points:

x = - 1033, x = 1033

Domain of

0.1 x + 24 + \frac{330}{x} : x < 0 or x > 0

Find intervals:

Increasing

: - \infty < x < - 1033,

Decreasing

: - 1033 < x < 0,

Decreasing

: 0 < x < 1033,

Increasing

: 1033 < x < \infty

Plug the extreme point

x = - 1033

into

0.1 x + 24 + \frac{330}{x} \Rightarrow y = 12.51087 \dots

Maximum (- 1033, 12.51087 \dots)

Plug the extreme point

x = 1033

into

0.1 x + 24 + \frac{330}{x} \Rightarrow y = 35.48912 \dots

Minimum (1033, 35.48912 \dots)

Maximum (- 1033, 12.51087 \dots), Minimum (1033, 35.48912 \dots)

(- 2) (6.12)

(1.4) (7.6)

f (x) = \frac{3}{x + 4}

y = arctan (\frac{x - 1}{x + 1})

(1.2) m = 2

What is the extreme f(x)=0.1x+24+((330)/x) ?
The extreme f(x)=0.1x+24+((330)/x) is Maximum(-10sqrt(33),12.51087…),Minimum(10sqrt(33),35.48912…)