What is the domain of f(x)=arctan(((x-1))/((x+1))) ?

The domain of f(x)=arctan(((x-1))/((x+1))) is x -1

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domain of f(x)=arctan(((x-1))/((x+1)))

domain

f (x) = arctan (\frac{( x - 1 )}{( x + 1 )})

x < - 1 or x > - 1

Interval Notation

(- \infty, - 1) \cup (- 1, \infty)

Solution steps

Find undefined (singularity) points:

x = - 1

The function domain

x < - 1 or x > - 1

3 x + 6

(- 4, - 3), (2, - 7)

2 - x

f (x) = \frac{3 x - 1}{( x + 3 ) ( x - 1 )}

e^{x + 4}

What is the domain of f(x)=arctan(((x-1))/((x+1))) ?
The domain of f(x)=arctan(((x-1))/((x+1))) is x<-1\lor x>-1