What is the inverse of f(x)=4pi*r^2 ?

The inverse of f(x)=4pi*r^2 is (sqrt(pi)sqrt(r))/(2pi),-(sqrt(pi)sqrt(r))/(2pi)

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inverse of f(x)=4pi*r^2

inverse

f (x) = 4 π \cdot r^{2}

\frac{π r}{2 π}, - \frac{π r}{2 π}

Solution steps

x = 4 π r^{2}

Replace

r

with

x

r = 4 π x^{2}

Solve for

x, r = 4 π \cdot x^{2}

\frac{π r}{2 π}, - \frac{π r}{2 π}

f (x) = x^{2} - ∣ x ∣

2 x^{2} + 15 x + 7

f (x) = - 8 x + 9

3 x^{2} - 8

f (x) = \frac{7}{x} + \frac{9}{x + 9}

What is the inverse of f(x)=4pi*r^2 ?
The inverse of f(x)=4pi*r^2 is (sqrt(pi)sqrt(r))/(2pi),-(sqrt(pi)sqrt(r))/(2pi)