What is the domain of f(x)=x^2+9,x>=-5 ?

The domain of f(x)=x^2+9,x>=-5 is x>=-5

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domain of f(x)=x^2+9,x>=-5

domain

f (x) = x^{2} + 9, x \geq - 5

x \geq - 5

Solution steps

Set the domain to the given interval

x \geq - 5

The function has no undefined points nor domain constraints. Therefore, the domain is

x \geq - 5

f (x) = (x + 7)^{8}

f (x) = \frac{x ^{4}}{2} + 3 x^{2} - 2 x

y = \frac{x ^{3}}{x ^{2} - 7}

g (x) = \frac{x ^{2} + 5}{x + 2}

What is the domain of f(x)=x^2+9,x>=-5 ?
The domain of f(x)=x^2+9,x>=-5 is x>=-5