What is the domain of f(x)= 1/(sqrt(x^2-5x)) ?

The domain of f(x)= 1/(sqrt(x^2-5x)) is x 5

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domain of f(x)= 1/(sqrt(x^2-5x))

domain

f (x) = \frac{1}{x ^{2} - 5 x}

x < 0 or x > 5

Interval Notation

(- \infty, 0) \cup (5, \infty)

Solution steps

Find non-negative values for radicals:

x \leq 0 or x \geq 5

Find undefined (singularity) points:

x = 5, x = 0

Combine real regions and undefined points for final function domain

x < 0 or x > 5

(6, - 2), (2, 1)

\frac{1}{1 - cos ( θ )}

7^{x} + 9

(- 4, - 4), (- 2, - 6)

2 x - 3 y = 18

What is the domain of f(x)= 1/(sqrt(x^2-5x)) ?
The domain of f(x)= 1/(sqrt(x^2-5x)) is x<0\lor x>5