What is the inverse of f(x)=25-x^2,x<= 25 ?

The inverse of f(x)=25-x^2,x<= 25 is sqrt(-x+25),-sqrt(-x+25)

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inverse of f(x)=25-x^2,x<= 25

inverse

f (x) = 25 - x^{2}, x \leq 25

- x + 25, - - x + 25

Solution steps

y = 25 - x^{2}

Replace

x

with

y

x = 25 - y^{2}

Solve for

y, x = 25 - y^{2}

- x + 25, - - x + 25

(5, 8), (10, 20)

f (x) = - (x - 1)^{2} + 5

3 x + 6 y = - 90

f (x) = \frac{2 x + 4}{3}

x e [\frac{1}{x}]

What is the inverse of f(x)=25-x^2,x<= 25 ?
The inverse of f(x)=25-x^2,x<= 25 is sqrt(-x+25),-sqrt(-x+25)