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Popular >

distance (5,8),(10,20)

Solution

distance

(5, 8), (10, 20)

Solution

13

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(5, 8)

and

(10, 20)

is

= (10 - 5)^{2} + (20 - 8)^{2}

Simplify

= 13

Popular Examples

monotone f(x)=-(x-1)^2+5 monotone intervals

f (x) = - (x - 1)^{2} + 5

parallel 3x+6y=-90 parallel

3 x + 6 y = - 90

inverse of f(x)=(sqrt(2x+4))/3 inverse

f (x) = \frac{2 x + 4}{3}

monotone xe[ 1/x ]monotone intervals

x e [\frac{1}{x}]

inverse of y=1-x/(10)inverse

y = 1 - \frac{x}{10}

Frequently Asked Questions (FAQ)

What is the distance (5,8),(10,20) ?
The distance (5,8),(10,20) is 13